Integrand size = 14, antiderivative size = 61 \[ \int x (a+b x)^5 (A+B x) \, dx=-\frac {a (A b-a B) (a+b x)^6}{6 b^3}+\frac {(A b-2 a B) (a+b x)^7}{7 b^3}+\frac {B (a+b x)^8}{8 b^3} \]
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Time = 0.03 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {77} \[ \int x (a+b x)^5 (A+B x) \, dx=\frac {(a+b x)^7 (A b-2 a B)}{7 b^3}-\frac {a (a+b x)^6 (A b-a B)}{6 b^3}+\frac {B (a+b x)^8}{8 b^3} \]
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Rule 77
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a (-A b+a B) (a+b x)^5}{b^2}+\frac {(A b-2 a B) (a+b x)^6}{b^2}+\frac {B (a+b x)^7}{b^2}\right ) \, dx \\ & = -\frac {a (A b-a B) (a+b x)^6}{6 b^3}+\frac {(A b-2 a B) (a+b x)^7}{7 b^3}+\frac {B (a+b x)^8}{8 b^3} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.89 \[ \int x (a+b x)^5 (A+B x) \, dx=\frac {1}{2} a^5 A x^2+\frac {1}{3} a^4 (5 A b+a B) x^3+\frac {5}{4} a^3 b (2 A b+a B) x^4+2 a^2 b^2 (A b+a B) x^5+\frac {5}{6} a b^3 (A b+2 a B) x^6+\frac {1}{7} b^4 (A b+5 a B) x^7+\frac {1}{8} b^5 B x^8 \]
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Leaf count of result is larger than twice the leaf count of optimal. \(120\) vs. \(2(55)=110\).
Time = 0.39 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.98
method | result | size |
norman | \(\frac {b^{5} B \,x^{8}}{8}+\left (\frac {1}{7} b^{5} A +\frac {5}{7} a \,b^{4} B \right ) x^{7}+\left (\frac {5}{6} a \,b^{4} A +\frac {5}{3} a^{2} b^{3} B \right ) x^{6}+\left (2 a^{2} b^{3} A +2 a^{3} b^{2} B \right ) x^{5}+\left (\frac {5}{2} a^{3} b^{2} A +\frac {5}{4} a^{4} b B \right ) x^{4}+\left (\frac {5}{3} a^{4} b A +\frac {1}{3} a^{5} B \right ) x^{3}+\frac {a^{5} A \,x^{2}}{2}\) | \(121\) |
default | \(\frac {b^{5} B \,x^{8}}{8}+\frac {\left (b^{5} A +5 a \,b^{4} B \right ) x^{7}}{7}+\frac {\left (5 a \,b^{4} A +10 a^{2} b^{3} B \right ) x^{6}}{6}+\frac {\left (10 a^{2} b^{3} A +10 a^{3} b^{2} B \right ) x^{5}}{5}+\frac {\left (10 a^{3} b^{2} A +5 a^{4} b B \right ) x^{4}}{4}+\frac {\left (5 a^{4} b A +a^{5} B \right ) x^{3}}{3}+\frac {a^{5} A \,x^{2}}{2}\) | \(124\) |
gosper | \(\frac {1}{8} b^{5} B \,x^{8}+\frac {1}{7} x^{7} b^{5} A +\frac {5}{7} x^{7} a \,b^{4} B +\frac {5}{6} x^{6} a \,b^{4} A +\frac {5}{3} x^{6} a^{2} b^{3} B +2 A \,a^{2} b^{3} x^{5}+2 B \,a^{3} b^{2} x^{5}+\frac {5}{2} x^{4} a^{3} b^{2} A +\frac {5}{4} x^{4} a^{4} b B +\frac {5}{3} x^{3} a^{4} b A +\frac {1}{3} x^{3} a^{5} B +\frac {1}{2} a^{5} A \,x^{2}\) | \(126\) |
risch | \(\frac {1}{8} b^{5} B \,x^{8}+\frac {1}{7} x^{7} b^{5} A +\frac {5}{7} x^{7} a \,b^{4} B +\frac {5}{6} x^{6} a \,b^{4} A +\frac {5}{3} x^{6} a^{2} b^{3} B +2 A \,a^{2} b^{3} x^{5}+2 B \,a^{3} b^{2} x^{5}+\frac {5}{2} x^{4} a^{3} b^{2} A +\frac {5}{4} x^{4} a^{4} b B +\frac {5}{3} x^{3} a^{4} b A +\frac {1}{3} x^{3} a^{5} B +\frac {1}{2} a^{5} A \,x^{2}\) | \(126\) |
parallelrisch | \(\frac {1}{8} b^{5} B \,x^{8}+\frac {1}{7} x^{7} b^{5} A +\frac {5}{7} x^{7} a \,b^{4} B +\frac {5}{6} x^{6} a \,b^{4} A +\frac {5}{3} x^{6} a^{2} b^{3} B +2 A \,a^{2} b^{3} x^{5}+2 B \,a^{3} b^{2} x^{5}+\frac {5}{2} x^{4} a^{3} b^{2} A +\frac {5}{4} x^{4} a^{4} b B +\frac {5}{3} x^{3} a^{4} b A +\frac {1}{3} x^{3} a^{5} B +\frac {1}{2} a^{5} A \,x^{2}\) | \(126\) |
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Leaf count of result is larger than twice the leaf count of optimal. 119 vs. \(2 (56) = 112\).
Time = 0.22 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.95 \[ \int x (a+b x)^5 (A+B x) \, dx=\frac {1}{8} \, B b^{5} x^{8} + \frac {1}{2} \, A a^{5} x^{2} + \frac {1}{7} \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{7} + \frac {5}{6} \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{6} + 2 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x^{5} + \frac {5}{4} \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{4} + \frac {1}{3} \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x^{3} \]
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Leaf count of result is larger than twice the leaf count of optimal. 134 vs. \(2 (54) = 108\).
Time = 0.03 (sec) , antiderivative size = 134, normalized size of antiderivative = 2.20 \[ \int x (a+b x)^5 (A+B x) \, dx=\frac {A a^{5} x^{2}}{2} + \frac {B b^{5} x^{8}}{8} + x^{7} \left (\frac {A b^{5}}{7} + \frac {5 B a b^{4}}{7}\right ) + x^{6} \cdot \left (\frac {5 A a b^{4}}{6} + \frac {5 B a^{2} b^{3}}{3}\right ) + x^{5} \cdot \left (2 A a^{2} b^{3} + 2 B a^{3} b^{2}\right ) + x^{4} \cdot \left (\frac {5 A a^{3} b^{2}}{2} + \frac {5 B a^{4} b}{4}\right ) + x^{3} \cdot \left (\frac {5 A a^{4} b}{3} + \frac {B a^{5}}{3}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 119 vs. \(2 (56) = 112\).
Time = 0.20 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.95 \[ \int x (a+b x)^5 (A+B x) \, dx=\frac {1}{8} \, B b^{5} x^{8} + \frac {1}{2} \, A a^{5} x^{2} + \frac {1}{7} \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{7} + \frac {5}{6} \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{6} + 2 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x^{5} + \frac {5}{4} \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{4} + \frac {1}{3} \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x^{3} \]
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Leaf count of result is larger than twice the leaf count of optimal. 125 vs. \(2 (56) = 112\).
Time = 0.27 (sec) , antiderivative size = 125, normalized size of antiderivative = 2.05 \[ \int x (a+b x)^5 (A+B x) \, dx=\frac {1}{8} \, B b^{5} x^{8} + \frac {5}{7} \, B a b^{4} x^{7} + \frac {1}{7} \, A b^{5} x^{7} + \frac {5}{3} \, B a^{2} b^{3} x^{6} + \frac {5}{6} \, A a b^{4} x^{6} + 2 \, B a^{3} b^{2} x^{5} + 2 \, A a^{2} b^{3} x^{5} + \frac {5}{4} \, B a^{4} b x^{4} + \frac {5}{2} \, A a^{3} b^{2} x^{4} + \frac {1}{3} \, B a^{5} x^{3} + \frac {5}{3} \, A a^{4} b x^{3} + \frac {1}{2} \, A a^{5} x^{2} \]
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Time = 0.07 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.75 \[ \int x (a+b x)^5 (A+B x) \, dx=x^3\,\left (\frac {B\,a^5}{3}+\frac {5\,A\,b\,a^4}{3}\right )+x^7\,\left (\frac {A\,b^5}{7}+\frac {5\,B\,a\,b^4}{7}\right )+\frac {A\,a^5\,x^2}{2}+\frac {B\,b^5\,x^8}{8}+2\,a^2\,b^2\,x^5\,\left (A\,b+B\,a\right )+\frac {5\,a^3\,b\,x^4\,\left (2\,A\,b+B\,a\right )}{4}+\frac {5\,a\,b^3\,x^6\,\left (A\,b+2\,B\,a\right )}{6} \]
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